Question

$(\frac{1}{2} x \frac{19}{7} ):( \frac{2}{4} - \frac{1}{6} )+3$

Answer 1

$\left(\dfrac{1}{2}\times \dfrac{19}{7} \right ):\left(\dfrac{2}{4}-\dfrac{1}{6} \right)+3\\ \\ =\left(\dfrac{1 \times 19}{2 \times 7} \right ):\left(\dfrac{3\times 2-2\times 1}{12} \right )+3\\ \\ =\dfrac{19}{14}:\left(\dfrac{6-2}{12} \right )+3\\ \\ =\dfrac{19}{14}:\dfrac{4}{12}+3\\ \\ =\dfrac{19}{14}:\dfrac{4^{:4}}{12^{:4}}+3\\ \\ =\dfrac{19}{14}:\dfrac{1}{3}+3\\ \\ =\dfrac{19}{14}\times\dfrac{3}{1}+3\\ \\ =\dfrac{19\times 3}{14 \times 1}+3\\ \\ =\dfrac{57}{14}+3\\ \\ =\dfrac{57+14\times 3}{14}\\ \\ =\dfrac{57+42}{14}\\ \\ =\dfrac{99}{14}$