Question

$\frac{1}{2} \sqrt[6]{32}$

Answer 1

$\frac{1}{2}.2^{ \frac{5}{6} }= 2^{ \frac{5}{6} - 1} = 2^{- \frac{1}{6} } = \boxed{\frac{1}{2^{6}} }$

Answer 2

Utilize propriedades das potências e das raízes:

$\frac{1}{2} \sqrt[6]{32}= \sqrt[6]{\frac{1}{4}.32}= \sqrt[6]{8}= \sqrt[6]{2^3}= \sqrt[3]{2}$