Question

$f(x)= \frac{x}{2} - \frac{3}{4} calculando \frac{f(0)-f(1)}{f(2)} obtemos A= - 4 B= 5 C= 3 D=-3 E=4$

Answer 1

Explicação passo-a-passo:

Temos que:

• f(0)

$\sf f(0)=\dfrac{0}{2}-\dfrac{3}{4}$

$\sf f(0)=0-\dfrac{3}{4}$

$\sf f(0)=\dfrac{-3}{4}$

• f(1)

$\sf f(1)=\dfrac{1}{2}-\dfrac{3}{4}$

$\sf f(1)=\dfrac{2-3}{4}$

$\sf f(1)=\dfrac{-1}{4}$

• f(2)

$\sf f(1)=\dfrac{2}{2}-\dfrac{3}{4}$

$\sf f(1)=\dfrac{4-3}{4}$

$\sf f(1)=\dfrac{1}{4}$

Logo:

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{\frac{-3}{4}-\Big(\frac{-1}{4}\Big)}{\frac{1}{4}}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{\frac{-3}{4}+\frac{1}{4}}{\frac{1}{4}}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{\frac{-3+1}{4}}{\frac{1}{4}}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{\frac{-2}{4}}{\frac{1}{4}}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{-2}{4}\cdot\dfrac{4}{1}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=\dfrac{-8}{4}$

$\sf \dfrac{f(0)-f(1)}{f(2)}=-2$