Question

$(a4-b4)/(a2-b2)-(a+b)^4/(a+b)^2+1/2a*root(3;27b3$

Answer 1

$=a4−b4a2−b2−(a+b)4(a+b)2+12a27b3−−−−√3= =(a2+b2)⋅(a2−b2)a2−b2−(a+b)4(a+b)2+12a27b3−−−−√3= =(a2+b2)−(a+b)4(a+b)2+12a27b3−−−−√3= =(a2+b2)−(a+b)2+12a27b3−−−−√3= =(a2+b2)−(a2+2ab+b2)+12a$