Question

$a)\sqrt{46} +\sqrt{16} = b)\sqrt[3]{8}+\sqrt[4]{16}= c)-5\sqrt{9}+2\sqrt{169}= d)10\sqrt[3]{2}+4\sqrt[3]{2}-\sqrt[3]{2}=$

Answer 1

$a)\sqrt{46} + \sqrt{16} = \sqrt{46} + 4\\b)\sqrt[3]{8} + \sqrt[4]{16} = 2 + 2 = 4\\c)-5\sqrt{9} + 2\sqrt{169} = -5(3) + 2(13) = -15 + 26 = 11\\d)10\sqrt[3]{2} + 4\sqrt[3]{2} - \sqrt[3]{2} = 13\sqrt[3]{2}$