Question

$9x = \sqrt[3]{81}$
como resolver??​

Answer 1

$9x=\sqrt[3]{81} \implies9x=\sqrt[3]{3^4} \implies9x=\sqrt[3]{3^3\cdot3} \implies\\\\9x=3\sqrt[3]{3} \implies3x=\sqrt[3]{3} \implies(3x)^3=(\sqrt[3]{3})^3\implies\\\\27x^3=3\implies x=\sqrt[3]{\dfrac{3}{27} } \implies x=\sqrt[3]{\dfrac{1}{9} }$