Question

${7x}^2 + x + 2 = 0{?}$
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Answer 1

Resposta:

Δ=b²-4ac

Δ=1²-4(7)(2)

Δ=1-56

Δ=-55

$\frac{-b +/- \sqrt{delta} }{2a}$

$\frac{-1 +/- \sqrt{-55} }{2(7)}$

$\frac{-1 +/- (-55) }{14}$

$\frac{-1 +(-55) }{14} = \frac{-1-55 }{14} = \frac{-56 }{14} = -4$

$\frac{-1 -(-55) }{14} = \frac{-1+55 }{14} = \frac{54 }{14} = 3,8$