Question

$(7 {}^{3} ) {}^{2} \times 7 {}^{ - 4}$
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Answer 1

(7³)² × 7-⁴ =7^6 × 7-4 = 7^(6-4)= 7² = 49

Answer 2

Resposta:

$49$

Explicação passo-a-passo:

$(7^{3})^2.7^{-4}  \\\\(7^{3.2}).\frac{1}{7^{4} } \\\\7^{6}.\frac{1}{7^{4} } \\\\\frac{7^{6} }{7^{4} } \\\\7^{6-4} \\7^{2} = 49$