Question

$- 6 \: \: \: {x}^{3} {y}^{4} \: \: - 12 \: { x}^{3} {y}^{4} \: \: + {x}^{3} {y}^{4} =$



$\frac{1}{4} \: a \: b \: c \: - \frac{ - 3}{4} \: a \: b \: c \: + \frac{7}{4} \: a \: b \: c \: =$

obs: esse dever não tem perguntas

​

Answer 1

a) - 6x^3y^4 - 12x^3y^4 + x^3y^4 = -17x^3y^4

b) 1/4abc - (-3/4abc) + 7/4abc

1/4abc + 3/4abc + 7/4abc = 11/4abc

®!