Question

$6 {x}^{2} - 5x + 1 = 0$
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Answer 1

6x^2 - 5x + 1 = 0

a = 6, b = -5 e c = 1

delta = b^2 - 4 * a * c
delta = (-5)^2 - 4 * 6 * 1
delta = 25 - 24
delta = 1

x = [-b +- delta^(1/2)]/2*a
x = [5 +- 1^(1/2)]/2*6
x = [5 +- 1]/12

x1 = [5 + 1]/12 = 6/12 = 1/2
x2 = [5 - 1]/12 = 4/12 = 1/3

Solução = {1/3, 1/2}