Question

$6 \times + 2 {x}^{2} = 130 - 9x + {x}^{2}$
agm sabe resolver?

Answer 1

$6x + 2 {x}^{2} = 130 - 9x + {x}^{2} \\ 2 {x}^{2} - {x}^{2} + 6x - 9x - 130 = 0 \\ {x}^{2} - 3x - 130 = 0 \\ \\ delta = 529 \\ \\ x = \frac{3 + 23}{2} = \frac{26}{2} = 13 \\ \\ x = \frac{3 - 23}{2} = \frac{ - 20}{2} = - 10$