Question

$6 ^{2} + \sqrt{36} - 16 ^{ - 1}$

​

Answer 1

$6^2+\sqrt{36}-16^{-1}\\\\=6^2+6-16^{-1}\\\\6^2=36\\\\=36+6-16^{-1}\\\\=36+6-\frac{1}{16}\\\\36+6=42\\\\=-\frac{1}{16}+42\\\\42=\frac{42\cdot \:16}{16}\\\\=\frac{42\cdot \:16}{16}-\frac{1}{16}\\\\=\frac{671}{16} >>> decimal >>> 41.9375$

Answer 2

Resposta:

671/16 ou 41,9375

Explicação passo-a-passo:

${a}^{ - n} = \frac{1}{ {a}^{n} }$

${6}^{2} + \sqrt{36} - {16}^{ - 1}$

$36 + 6 - \frac{1}{ {16}^{1} }$

$42 - \frac{1}{16}$

$\frac{42}{1} - \frac{1}{16} = \frac{(42 \times 16) - 1}{16}$

$\frac{672 - 1}{16} = \frac{671}{16}$

= 41,9375