Question

$5 \sqrt{8} - 2 \sqrt{18} + \frac{1}{2} \sqrt{200}$
adição algébrica de radicais por favor me ajudem ​

Answer 1

8/2

4/2

2/2

1

$8 = 2 \times {2}^{2}$

18/2

9/3

3/3

1

$18 = 2 \times {3}^{2}$

200/2

100/2

50/2

25/5

5/5

1

$200 = 2 \times {2}^{2} \times {5}^{2}$

$5 \sqrt{8} - 2 \sqrt{18} + \frac{1}{2} \sqrt{200} = \\ 5 \sqrt{2 \times {2}^{2} } - 2 \sqrt{2 \times {3}^{2} } + \frac{1}{2} \sqrt{2 \times {2}^{2} \times {5}^{2} } = \\ 5 \times 2 \sqrt{2} - 2 \times 3 \sqrt{2} + \frac{1}{2} \times 2 \times 5 \sqrt{2} = \\ 10 \sqrt{2} - 6 \sqrt{2} + 5 \sqrt{2} = \\ 9 \sqrt{2}$