![5\sqrt{2} ^{2} = x^{2} +x^{2} \\\\\\3\sqrt{3} ^{2} = x^{2} +x^{2} \\\\\\10^{2} = x^{2} +x^{2} \\\\\\25^{2} = x^{2} + x^{2} 5\sqrt{2} ^{2} = x^{2} +x^{2} \\\\\\3\sqrt{3} ^{2} = x^{2} +x^{2} \\\\\\10^{2} = x^{2} +x^{2} \\\\\\25^{2} = x^{2} + x^{2}](https://tex.z-dn.net/?f=5%5Csqrt%7B2%7D+%5E%7B2%7D+%3D+x%5E%7B2%7D+%2Bx%5E%7B2%7D+%5C%5C%5C%5C%5C%5C3%5Csqrt%7B3%7D+%5E%7B2%7D+%3D+x%5E%7B2%7D+%2Bx%5E%7B2%7D+%5C%5C%5C%5C%5C%5C10%5E%7B2%7D+%3D+x%5E%7B2%7D+%2Bx%5E%7B2%7D+%5C%5C%5C%5C%5C%5C25%5E%7B2%7D+%3D+x%5E%7B2%7D+%2B+x%5E%7B2%7D)
Teorema de Pitágoras
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Resposta:
Explicação passo a passo:
(5V2)²=x²+x²
25.2=2x²
2x²=50
x²=50/2
x²=25
x=V25
x=5
(3V3)²=x²+x²
9.3=2x²
2x²=27
x²=27/2
x=V27/2
x=V27/V2+V2/V2
x=V54/2
x=3V6/2
10²=x²+x²
100=2x²
x²=100/2
x²=50
x=V50
x=5V2
25²=x²+x²
625=2x²
x²=625/2
x=V625/2
x=V625/V2.V2/V2
x=V1250/V4
x=25V2/2
joaopedrotoledo075:
Obrigado :)
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