Question

$3 {x}^{2} - 10x - 8 = 0$
Equação de 2° grau!!​

Answer 1

∆ = (-10)² - 4.3.(-8)

∆ = 100 + 96

∆ = 196

$x = \frac{ - ( - 10) + - \sqrt{196} }{2 \times 3}$

$x = \frac{10 + - 14}{6}$

$x1 = \frac{10 + 14}{6} = 4 \\ x2 = \frac{10 - 14}{6} = - \frac{2}{3}$

Answer 2

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~3x^{2}-10x-8=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=3{;}~b=-10~e~c=-8\\\\\Delta=(b)^{2}-4(a)(c)=(-10)^{2}-4(3)(-8)=100-(-96)=196\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-10)-\sqrt{196}}{2(3)}=\frac{10-14}{6}=\frac{-4\div2}{6\div2}=-\frac{2}{3} \\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-10)+\sqrt{196}}{2(3)}=\frac{10+14}{6}=\frac{24}{6}=4\\\\S=\{-\frac{2}{3} ,~4\}$