Question

$(2x - 1) {x}^{2} - x \times 2 = 0$
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Answer 1

Resposta:

$(2x - 1) {x}^{2} - x \times 2 = 0$

$2x - 1 \times {x}^{2} - x \times 2 = 0$

${x}^{2} + 2x - x \times 2 - 1 = 0$

${x}^{2} + x \times 1 = 0$

${x}^{2} + x = 0$

A=1 B=1 C=0

$Delta= b^2-4ac$

$delta= 1-4×1×0$

$delta = 1$

$x = \frac{- b + - \sqrt{delta}}{2 \times a}$

$x = \frac{ - 1 + - \sqrt{1}}{2 \times 1}$

$x1 = \frac{ - 1 + 1}{2}$

$x1 = 0$

$x2 = \frac{ - 1 - 1}{2}$

$x2 = - 1$

ou seja

x1=0

x2=-1