Question

${2}^{x} \times {4}^{x + 1} \times {8}^{x + 2} = {16}^{x + 3}$
Me ajudem!!!

Answer 1

$2^x\times4^{x+1}\times8^{x+2}=16^{x+3} \\ \\ 2^x\times2^{2(x+1)}\times2^{3(x+2)}=2^{4(x+3)} \\ \\ 2^{x}\times2^{2x+2}}\times2^{3x+6}=2^{4x+12} \\ \\ 2^{x+2x+2+3x+6}=2^{4x+12} \\ \\ \not2^{6x+8}=\not2^{4x+12} \\ \\ 6x+8=4x+12 \\ \\ 6x-4x=12-8 \\ \\ 2x=4 \\ \\ x=4\div2 \\ \\ x=2$