Question

 $2 x^{2} +5x-3=0$

Answer 1

$2x^{2}+5x-3=0\\ \\ 2x^{2}+2x+3x-3=0\\ \\ 2x\left(x+1 \right )-3\cdot\left(x+1 \right )=0\\ \\ \left(x+1 \right )\cdot\left(2x-3 \right )=0\\ \\ \begin{array}{rcl} x+1=0&\text{ ou }&2x-3=0 \end{array}\\ \\ \begin{array}{rcl} x=-1&\text{ ou }&2x=3 \end{array}\\ \\ \boxed{\begin{array}{rcl} x=-1&\text{ ou }&x=\dfrac{3}{2} \end{array}\\ \\ }$