Question

$- 2 { \times }^{2} + 6 \times - 4 = 0$
resolva ​

Answer 1

Resposta: {2,1}

-2x² + 6x - 4 = 0

a= -2

b= 6

c= -4

Δ= b² - 4ac

Δ = 6² - 4.(-2) . (-4)

Δ = 36 - 32

Δ = 4

x' = (-6 + √4) : 2.(-2) ∴ x' = (-6 +2)/-4 ∴ x' = -4/-4∴ x' = 1

x'' = (-6 - 2)/-4 ∴x'' = -8/-4 ∴x'' = 2