Question

$( 2\sqrt{3} )^{-1}$

Answer 1

$(2\sqrt{3})^{-1}=\dfrac{1}{2\sqrt{3}}$

Racionalizando:

$\dfrac{1}{2\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{\sqrt{3}}{2\cdot3}=\dfrac{\sqrt{3}}{6}$

$(2\sqrt{3})^{-1}=\dfrac{\sqrt{3}}{6}$

Answer 2

Boa noite!

$(2 \sqrt{3} )^-^1=\\ \\ \frac{1}{2 \sqrt{3} } \\ \\ racionalizando..\\ \\ \frac{1}{2 \sqrt{3} } . \frac{ \sqrt{3} }{ \sqrt{3} } =\\ \\ \frac{ \sqrt{3} }{2( \sqrt{3})^2 } =\\ \\ \frac{ \sqrt{3} }{2.3} =\\ \\ \frac{ \sqrt{3} }{6} \;\ \textless \ -- resposta.\\ \\ Bons\;estudos!$