Question

∛($2^{28}+ 2^{30})/10$

Answer 1

$\\\frac{\sqrt[3]{2^{28}+2^{30}}}{10}=\\\\\frac{\sqrt[3]{2^{27}(2^1+2^3)}}{10}=\\\\\frac{2^9\sqrt[3]{2+8}}{10}=\\\\\frac{2^8\sqrt[3]{10}}{5}=\\\\\boxed{\frac{256\sqrt[3]{10}}{5}}$