Question

${2}^{ - 1} + 6.( \frac{2}{3} ) { }^{ - 2} - ( \frac{ - 1}{3} ) {}^{ - 1}$

Answer 1

Resposta:

${2}^{ - 1} + 6( \frac{2}{3})^{ - 2} - (\frac{ - 1}{3} )^{ - 1} = \\ \frac{1}{2} + 6( \frac{3}{2} )^{2} - ( - 3) = \\ \frac{1}{2} + 6( \frac{9}{4} ) + 3 = \\ \frac{1}{2} + 3( \frac{9}{2} ) + 3 = \\ \frac{1}{2} + \frac{27}{2} + 3 = \\ \frac{1 + 27 + 3(2)}{2} = \\ \frac{28 + 6}{2} = \\ \frac{34}{2} = 17$