Question

$( 2^{-1} + 2^{-2})^{-2}$ alguém me explica passo a passo pf

Answer 1

Ola

$(\dfrac{1}{2^{1}} + \dfrac{1}{2^{2}})^{-2}$

$(\dfrac{1}{2} + \dfrac{1}{4})^{-2}$

$(\dfrac{3}{4})^{-2}$

$(\dfrac{1}{(\dfrac{3}{4})^{2}})$

$\dfrac{1}{\dfrac{9}{16}}$

$\dfrac{(\dfrac{1}{1}}{\dfrac{9}{16}})$

Usando a fórmula $\dfrac{a(d)}{b(c)}$, temos

$\dfrac{1(16)}{1(9)}$

$\dfrac{16}{9}$

Resposta:
$\boxed{S = (\frac{16}{9})}$