Question

${1 }^{2}$
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Answer 1

Resposta:

3)

a)

$\sqrt{121} = {\sqrt{ { \blue{11}}^{2} } } = \Large \boxed{ \green{ 11}}$

4)

$\frac{1}{3} - \left( - \frac{1}{2} + \frac{1}{3} \right) + \left( - \frac{2}{3} - 1\right) \\ \\ \frac{1}{3 } - \left( \frac{ - 3 \times 1 + 2 \times 1}{6} \right) + \left( \frac{ - 1 \times2 - 3 \times 1}{3} \right) \\ \\ \frac{1}{3} - \left( \frac{ - 3 + 2}{6} \right) + \left( \frac{ - 2 - 3 }{3} \right) \\ \\ \frac{1}{3} - \left( - \frac{ 1}{6} \right) + \left( - \frac{ 5}{3} \right) \\ \\ \frac{1}{3} + \frac{1}{6} - \frac{5}{3} \\ \\ \frac{6 \times 1 + 3 \times 1 - 6 \times 5}{18} \\ \\ \frac{6 + 3 - 30}{18} \\ \\ \frac{9 - 30}{18} \\ \\ - \frac{21 \div 3 }{18 \div 3} \\ \\ \Large \boxed{ \green{ \bf \: - \frac{7}{6} }} \\ \\ \Large \boxed{ \underline{ \blue{ \bf \: Bons \: Estudos!} \: 11 \:/05 \:/ 2021}}$