Question

${0.6}^{2} + \sqrt{0.81}$
?????​

Answer 1

$0. {6}^{2} + \sqrt{0.81} \\ ( \frac{6}{10} {)}^{2} + \sqrt{ \frac{81}{100} } \\ \frac{36}{100} + \frac{9}{10} \\ \frac{3.6}{10} + \frac{9}{10} = \frac{12.6}{10} = 1.26$