Question

$(0,5)^{2x}= 2^{1-3x}$

Answer 1

$(0,5)^{2x}=2^{1-3x}\\ (\frac{1}{2})^{2x}=2^{1-3x}\\ (2^{-1})^{2x}=2^{1-3x}\\ 2^{-2x}=2^{1-3x}\\ -2x=1-3x\\ -2x+3x=1\\ \boxed{x=1}$