Question

Teorema de Tales
Matemática ​

Answer 1

Resposta:

x = $\frac{3\sqrt{14} }{7 }$

Explicação passo a passo:

Aplicando o teorema de tales:

3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =  $\sqrt{\frac{18}{7} }$ = $\frac{\sqrt{18} }{\sqrt{7} }$*$\frac{\sqrt{7} }{\sqrt{7} }$ = $\frac{\sqrt{18}*\sqrt{7} }{7}$

->x = $\frac{\sqrt{126} }{7 }$ = $\frac{3*\sqrt{14} }{7 }$

Answer 2

Resposta:

x =

Explicação passo a passo:

Aplicando o teorema de tales:

3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =   = * =

->x =  = 3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =   = * =

->x =  = 3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =   = * =

->x =  = 3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =   = * =

->x =  = 3x/(x + 6) = (x + 3)/(x + 3 + x)

-> (x + 6)*(x + 3) = 3x*(2x + 3)

-> x^2 + 9x + 18 = 6x^2 + 9x

-> 7x^2 = 18 -> x^2 = 18/7

->x =   = * =

->x =  =