Question

teorema de Pitágoras: X²= (√10)²+(√10)²

Answer 1

$(\sqrt{10}) ^{2} = 10$
$x^{2} = 10+10 \\ \\ x^{2} =20 \\ \\ x = \sqrt{20} = 2 \sqrt{5}$

Answer 2

$x^2 = ( \sqrt{10})^2 + ( \sqrt{10})^2 \\ x^2 = 10+10 \\ x^2 = 20 \\ x = \sqrt{20} \\ \\ x = 2 \sqrt{5}$