Question

teorema de Pitágoras, determine o valor de x nos triangulos e retangulos​

Answer 1

${(x + 1)}^{2} = {x}^{2} + { \sqrt{ 7} }^{2} \\ {x}^{2} + 2x + 1 = {x}^{2} + 7 \\ 2x + 1 = 7 \\ 2x = 6 \\ x = 6 \div 2 \\ x = 3$