Question

teorema de pitagoras como caucula um triangulo retangulo com os dois catetos raiz de 10 e hipotenusa x ??

Answer 1

Olá, Renata.

 

$<var>[cateto]^2+[cateto]^2=[hipotenusa]^2</var>$

 

$<var> \Rightarrow (\sqrt{10})^2+(\sqrt{10})^2=[hipotenusa]^2</var>$

 

$<var>\Rightarrow [hipotenusa]^2=10+10</var>$

 

$<var> \Rightarrow [hipotenusa]^2=20 \Rightarrow [hipotenusa]=\sqrt{20}=\sqrt{2^2 \cdot 5}</var>$

 

$<var> \Rightarrow [hipotenusa] = 2\sqrt5</var>$

Answer 2

$<var>h^2=(\sqrt{10})^2+(\sqrt{10})^2 \\h^2=10+10=20 \\h=\sqrt{20}=\sqrt{2^2*5}\\h=2\sqrt5</var>$

 

ou

$<var>h=cat\sqrt{2}\\h=\sqrt{10}*\sqrt{2}\\h=\sqrt{20}\\h=\sqrt{2^2*5}\\ h=2\sqrt{5}</var>$