Question

Teorema de Pitágoras

Answer 1

Resposta:

1) x^2+8^2+6^2

x^2=64+36

x^2=100

$x = \sqrt{100} \\ x = 10 \: u.c.$

x^2=5^2+12^2

x^2=25+144

x^2=169

$x = \sqrt{169} \\ x =13u.c.$

x^2+8^2=10^2

x^2+64=100

x^2=100-64

x^2=36

$x = \sqrt{36} \\ x = 6u.c.$

2)

x^2=40^2+(25-15)^2

x^2=1600+(10)^2

x^2=1600+100

x^2=1700

$x = \sqrt{1700} \\ x = \sqrt{100 \times 17} \\ x = 10 \sqrt{17}metros$

3) x^2=27^2+36^2

x^2=729+1296

x^2=2025

$x = \sqrt{2025} \\ x = 45 \: cm$

Explicação passo-a-passo:

BONS ESTUDOS!

Answer 2

Explicação passo-a-passo:

1)

a)

$\sf x^2=6^2+8^2$

$\sf x^2=36+64$

$\sf x^2=100$

$\sf x=\sqrt{100}$

$\sf \red{x=10}$

b)

$\sf x^2=5^2+12^2$

$\sf x^2=25+144$

$\sf x^2=169$

$\sf x=\sqrt{169}$

$\sf \red{x=13}$

c)

$\sf x^2+8^2=10^2$

$\sf x^2+64=100$

$\sf x^2=100-64$

$\sf x^2=36$

$\sf x=\sqrt{36}$

$\sf \red{x=6}$

2)

$\sf x^2=(25-15)^2+40^2$

$\sf x^2=10^2+40^2$

$\sf x^2=100+1600$

$\sf x^2=1700$

$\sf x=\sqrt{1700}$

$\sf \red{x=10\sqrt{17}~m}$

3)

$\sf x^2=27^2+36^2$

$\sf x^2=729+1296$

$\sf x^2=2025$

$\sf x=\sqrt{2025}$

$\sf \red{x=45~cm}$