Question

Tente responder a esta pergunta: Quais são as medidas aproximadas das frentes dos lotes 1 e 2? 

Answer 1

Pelo Teorema de Tales:

$\dfrac{12}{13,50}=\dfrac{x}{15,40}$

$13,50x=12\times15,40$

$x=\dfrac{12\times15,40}{13,50}$

$x\approx13,68~\text{m}$

$\dfrac{12}{13,50}=\dfrac{y}{16,30}$

$13,50y=12\times16,30$

$y=\dfrac{12\times16,30}{13,50}$

$y\approx14,48~\text{m}$