Question

TEM UM DOIS ECIMA DO parente PERTO DO TRES ( X - 3) + 4 ( X - 1) ( X +6 ) = 180 DELTA

Answer 1

$(x - 3)^2 + 4(x - 1)(x + 6) = 180 \\ \\ x^2 - 6x + 9 + 4 (x^2 + 5x - 6) = 180 \\ \\ x^2 - 6x + 9 + 4x^2 + 20x - 24 = 180 \\ \\ 5x~2 + 14x - 15 = 180 \\ \\ => 5x^2 + 14x - 195 = 0$

===

a=5, b=14, c=−195

Δ=b²−4ac
Δ=(14)²−4*5*−195
Δ=196+3900
Δ=4096

===

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$x = \dfrac{-14 \pm \sqrt{4096}}{2*5} \\ \\ \\ x = \dfrac{-14 \pm 64}{10} \\ \\ \\ x' = \dfrac{-14 + 64}{10} \\ \\ \\ x' = \dfrac{50}{10} \\ \\ \\ x' = 5 \\ \\ \\ x'' = \dfrac{-14 - 64}{10} \\ \\ \\ x'' = \dfrac{-78}{10} x'' = \dfrac{-39}{5}$


S = {$5, \ \ \dfrac{-39}{5}$}