Question

tangente 150+2 seno 120 -cos 330=?

Answer 1

Olá,

tg150° = -tg30° = -√3/3
sen120° = sen60° = √3/2
cos330° = cos30° = √3/2

tg150 + 2sen120 - cos330
-√3/3 + 2*√3/2 - √3/2
-√3/3 + 2√3/2 - √3/2
-√3/3 + √3/2
(-2√3 + 3√3)/6
√3/6

Bons estudos ;)