Question

t4 - 12t2 + 35 = 0

equação biquadrada, cálculo pfvr

Answer 1

t^4-12t^2+35=0
(t^2)^2-12t^2+35=0
t^2= t
t^2-12t+35=0
∆= b^2-4.a.c
∆= (-12)^2-4.1.35
∆= 144-144
∆=0
x= -b+-√∆
-------------
___2.a

x=-(-12)+√0
-----------------
____2.1

x= +12/2
x=6