Question

Tʀɨռօʍɨօs ɖɛ 2 ɢʀaʊ ×2+17×+32

Answer 1

Olá,

x²+17x+32 = 0 sendo a = 1, b = 17 e c = 32

Δ = b²-4ac
Δ = (17)²-4(1)(32)
Δ = 289-128
Δ = 161

x₁ = (-b+√Δ)/2a = (-17+√161)/2(1) = (-17+√161)/2 = -17/2 + √161/2
x₂ = (-b-√Δ)/2a = (-17-√161)/2(1) = (-17-√161)/2 = -17/2 - √161/2

Resposta:

x = -17/2 + √161/2 ou x = -17/2 - √161/2