Question

(t-1)2=3t+1
(5 + x)2- 10(x + 5)=0
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Answer 1

(t—1)2 = 3t + 1

2t—2 = 3t + 1

2t — 3t = 1+2

—t = 3

t = —3

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(5+x)2—10(x+5)=0

10+2x—10x—50=0

2x—10x = —50—10

—8x = —60

x = —60/—8

x = 7,5