Question

Supondo Z=a+bi
3(a+bi)+(a+bi)i=2+34i​

Answer 1

3a+3bi+ai+bi²=2+34i

3a+3bi+ai-b=2+34i  

3a-b+(3bi+ai)=2+34i

3a-b+(a+3b)i=2+34i

3a-b=2  

a+3b=34

9a-3b=6

a+3b=34

10a=40

a=40

3(-4)-b=2

12-b=2

-b=2-12

-b=-10x(-1)

B=10

Z=4+10i