Question

Supondo que Sen(t)=0,8 e Cos(t)=0,6. Calcule o Sen(2t) e o Cos(2t).

Answer 1

$\mathsf{sen(2t)=2.sen(t).cos(t)=2.0,8.0,6=0,96}$

$\mathsf{cos(2t)=cos^2(t)-sen^2(t)} \\\mathsf{=0,6^2-0,8^2=0,36-0,64=-0,28}$