Question

SUPONDO LOG2=0,3, LOG5=0,7 E LOG7=0,8, O VALOR APROXIMADO DE LOG2 35 É?

Answer 1

Oi

log2(35) = log(35)/log(2) = (log(5) + log(7))/log(2) = 

(0.7 + 0.8)/0.3 = 1.5/0.3 = 15/3 = 5