Question

subtitua as letras pelos valores e calcule o valor númerico na formula de Bhaskara

b) a= 1 b= 8 c= 16
c) a=3 b= -2 c= -1
d) a=-1 b= -8 c=33
e) a=5 b= -8 c= -1
f) a=1 b= -4 c=5

Answer 1

$(-b+-\sqrt{b^2-4ac} )2a$

A -

$[3+-\sqrt{(-3)^2-4(-1)(4)} ]/2(-1)\\(3+-\sqrt{9+16} /)/-2\\(3+-5)/-2\\x'=3+5/-2 = 8/-2 = -4\\x''=3-5/-2 = -2/-2 = 1$

B -

$x = [-8+-\sqrt{(8)^2-4(1)*(16)} ]/2(1)\\x = (-8+-\sqrt{64-64})/2 \\x=-8+0/2 = 4$

C -

$x = [2+-\sqrt{(-2)^2-4(-1)(-1)}]/2*3 \\x = (2+-\sqrt{4-4} )/6\\x = 2+0/6 = 1/3$

D -

$x = [8+-\sqrt{(-8)^2-4(-1)(33)} ]/2(-1)\\x = (8+-\sqrt{64+132})/-2\\x = (8+-\sqrt{196} /-2 = (8+-14)/-2\\x'= 8-14/-2=-6/-2 = 3\\x''= 8-(-14)/-2 = 8+14/-2 = -11$

E -

$x = [-4+-\sqrt{(-4)^2-4(5)(-1)}/2(5)\\x = (-4+-\sqrt{16+20} )/10\\x = (-4+-6)/10\\x' = -4 -6/10 = -10/10 = -1\\x''= -4+6/10 = 2/10 = 1/5$

F -

$x = [4+-\sqrt{(-4)^2-4(1)(-5)} ]/2(1)\\x = (4+-\sqrt{16+20} )/2\\x = (4+-6)/2\\x'=4+6/2 = 10/2 = 5\\x''=4-6/2 = -2/2 = -1$

Espero ter ajudado ;)