Question

solucione as equações a)2x^2+2x-4=0

b)x^2-6x+5=0

Answer 1

a) 2x²+2x-4=0
∆=b²-4.a.c
∆=(2)²-4.2.-4
∆=4+32
X=-b±-√∆ /2.a
X=-2+-√36 /4
X'=-2+6/4= 1
X''=-2-6/4= -2


b) x² -6x +5
∆=(-6)²-4.1.5
∆=36-20
∆=16
X=-(-6)+-√16 /2.1
X'=6+4 /2 = 5
X''= 6-4 /2 = 1