Question

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Determine os coeficientes A,B e C da equação 3(-2X + 4) - 7X² - 1 = (X+1)²

Answer 1

3(-2x+4)-7x²-1=(x+1)²
-6x+12-7x²-1=x²+2x+1
-7x²-x²-6x+11-1=0
-8x²-6x-2x+10=0
-8x²-8x+10

A=-8
B=-8
C=10

Answer 2

3 (- 2x + 4) - 7x² - 1 = (x + 1)²
- 6x + 12 - 7x² - 1 = x² + 2x + 1
- 7x² - x² - 6x - 2x + 12 - 1 - 1
- 8x² - 8x + 10 = 0

Resp.: a = - 8; b = - 8; c = 10

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