Question

socorro ??? por favor mim responda direito, porque eu também quero entender a resposta

Answer 1

Resposta:

Explicação passo-a-passo:

Temos:

$A=\left[\begin{array}{ccc}2&1\\3&-1\\\end{array}\right]$

$B=\left[\begin{array}{ccc}-1&2\\1&0\\\end{array}\right]$

$C=\left[\begin{array}{ccc}4&-1\\2&1\\\end{array}\right]$

$X=\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]$

Agora, temos que

$\frac{\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]-\left[\begin{array}{ccc}2&1\\3&-1\\\end{array}\right]}{2}=\frac{\left[\begin{array}{ccc}-1&2\\1&0\\\end{array}\right]+\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]}{3}+\left[\begin{array}{ccc}4&-1\\2&1\\\end{array}\right]$

$\frac{\left[\begin{array}{ccc}a-2&b-1\\c-3&d+1\\\end{array}\right]}{2}=\frac{\left[\begin{array}{ccc}-1+a&2+b\\1+c&0+d\\\end{array}\right] }{3}+\left[\begin{array}{ccc}4&-1\\2&1\\\end{array}\right]$

$3\left[\begin{array}{ccc}a-2&b-1\\c-3&d+1\\\end{array}\right]=2\left[\begin{array}{ccc}-1+a&2+b\\1+c&0+d\\\end{array}\right]+6\left[\begin{array}{ccc}4&-1\\2&1\\\end{array}\right]$

$\left[\begin{array}{ccc}3a-6&3b-3\\3c-9&3d+3\\\end{array}\right]=\left[\begin{array}{ccc}-2+2a&4+2b\\2+2c&2d\\\end{array}\right]=\left[\begin{array}{ccc}24&-6\\12&6\\\end{array}\right]$

$\left[\begin{array}{ccc}3a-6&3b-3\\3c-9&3d+3\\\end{array}\right]-\left[\begin{array}{ccc}-2+2a&4+2b\\2+2c&2d\\\end{array}\right]=\left[\begin{array}{ccc}24&-6\\12&6\\\end{array}\right]$

$\left[\begin{array}{ccc}a-4&b-7\\c-11&d+3\\\end{array}\right]=\left[\begin{array}{ccc}24&-6\\12&6\\\end{array}\right]$

Temos agora que

a - 4 = 24 => a= 24 + 4 => a = 28

b - 7 = -6 => b = -6 + 7 => b = 1

s - 11 = 12 => c = 12 + 11=> c = 23

d + 3 = 6 => d = 6 - 3 => c = 3

Portanto

$X=\left[\begin{array}{ccc}28&1\\23&3\\\end{array}\right]$