Question

Socorro Me Ajudem ja tentei mais nao consegui obs: me ajudem na C, E, F

Answer 1

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Ola SrReeh

a) 

64^x = 256

2^6x = 2^8

6x = 8

x = 8/6 = 4/3

b)

25^(x + 2) = 125^(x + 5)

5^(2x + 4) = 5^(3x + 15)

2x + 4 = 3x + 15

x = -11 

c)

(8/125)^(2x - 1) = (25/4)^2x

(2/5(^(6x - 3) = (2/5(^-4x

6x - 3 = - 4x 

6x + 4x = 3

x = 3/10 

d)

5^(2x - 1) = 1

5^(2x - 1) = 5^0

2x - 1 = 0

2x = 1

x = 1/2

e)

7^x = 8^x

(7/8)^x = 1 = (7/8)^0

x = 0 

f)

³√25^x = √5

25^x = 5√5

5^2x = 5^(1+1/2)= 5^(3/2)

2x = 3/2

x = 3/4

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