Question

socorro me ajudem!
calcule o valor de y em cada equação

a) log4 y=3
b)logy 36=2

Answer 1

a) 
$Log_{4}y=3 \\ y= \frac{3}{ Log_{4}} \\ y=2,16404...$

b)
$Log_{y}36=2 \\ \\ \frac{Log36}{Logy}=2 \\ \\\frac{Logy}{Log36}= \frac{1}{2} \\ \\ Log(y)= \frac{Log(36)}{2} \\ \\ Log(y)= Log( \sqrt{36} ) \\ \\ Log(y)=Log(6) \\ \\ y=6$