SOCORRO AMORES!! Simplifique e calcule o valor de n:
Anexos:
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gabycoelhooo:
SOCORROOOOOOOOOOOO
Soluções para a tarefa
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Gaby
1° desenvolver os fatoriais convenientemente
2° simplificar: desaparecem fatoriais
3° efetuar operações
4° reduzir termos semelhantes
5° resolver a equação resultante
![\frac{n!}{(n+2)!+(n+1)!} = \frac{1}{48} \\ \\ \frac{n!}{(n+2)(n+1)n!+(n+1)n!} = \frac{1}{48} \\ \\ \frac{n!}{n!(n+1)[(n+2)+(1)]} = \frac{1}{48} \\ \\ \frac{1}{(n+1)(n+3)} = \frac{1}{48} \\ \\ 48=n^2+4n+3 \\ \\ n^2+4n-45=0 \\ \\ (n-5)(n+9)=0 \frac{n!}{(n+2)!+(n+1)!} = \frac{1}{48} \\ \\ \frac{n!}{(n+2)(n+1)n!+(n+1)n!} = \frac{1}{48} \\ \\ \frac{n!}{n!(n+1)[(n+2)+(1)]} = \frac{1}{48} \\ \\ \frac{1}{(n+1)(n+3)} = \frac{1}{48} \\ \\ 48=n^2+4n+3 \\ \\ n^2+4n-45=0 \\ \\ (n-5)(n+9)=0](https://tex.z-dn.net/?f=+%5Cfrac%7Bn%21%7D%7B%28n%2B2%29%21%2B%28n%2B1%29%21%7D+%3D+%5Cfrac%7B1%7D%7B48%7D+%5C%5C++%5C%5C++%5Cfrac%7Bn%21%7D%7B%28n%2B2%29%28n%2B1%29n%21%2B%28n%2B1%29n%21%7D+%3D+%5Cfrac%7B1%7D%7B48%7D++%5C%5C++%5C%5C++%5Cfrac%7Bn%21%7D%7Bn%21%28n%2B1%29%5B%28n%2B2%29%2B%281%29%5D%7D+%3D+%5Cfrac%7B1%7D%7B48%7D++%5C%5C++%5C%5C++%5Cfrac%7B1%7D%7B%28n%2B1%29%28n%2B3%29%7D++%3D+%5Cfrac%7B1%7D%7B48%7D+++%5C%5C++%5C%5C+48%3Dn%5E2%2B4n%2B3+%5C%5C++%5C%5C+n%5E2%2B4n-45%3D0+%5C%5C++%5C%5C+%28n-5%29%28n%2B9%29%3D0)
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S = { - 9, 5 }
1° desenvolver os fatoriais convenientemente
2° simplificar: desaparecem fatoriais
3° efetuar operações
4° reduzir termos semelhantes
5° resolver a equação resultante
S = { - 9, 5 }
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