SOCORRO ALGUÉM ME AJUDA POR FAVOR
valendo 100 pontos
Soluções para a tarefa
Resposta:
Explicação passo-a-passo:
a)
_2a² - 5 -a² - 3 + 9 - a²_ = _1_
a² a²
b)
_x² -2xy+ y²_ = _(x - y)²_
x²y² x²y²
c)
_a - b_ - __2__ + __1__
a(a + b) a + b b
m.m.c => ab(a + b)
_(a- b)b - 2ab + a(a + b)_
ab(a + b)
_ab - b² - 2ab + a² + ab_
ab(a + b)
_a² - b²_ = _(a + b)(a - b)_ = _(a - b)_
ab(a + b) ab(a + b) ab
d)
1 - __x²__ + __y²__ - __y__
x(x + y) y(x + y) x + y
m.m.c => xy(x + y)
_xy(x + y) - x²y + xy² - xy²_
xy(x + y)
_x²y + xy² - x²y + xy² - xy²_
xy(x + y)
__xy²__ = __y__
xy(x + y) x + y
e)
_3a + 1_ - _a + 1_
2(a - 1) a - 1
m.m.c => 2(a - 1)
_3a + 1 -2a - 2_ = _a - 1_ = _1_
2(a -1) 2(a - 1) 2
f)
__x__ + ___2y²__ + __y__
x - y (x + y)(x - y) x + y
m.m.c => (x + y)(x - y)
__x(x + y) + 2y² + y(x - y)_
(x + y)(x - y)
_x² + xy + 2y² + xy - y²_
(x + y)(x - y)
_x²+ 2xy + y^2_ = _(x + y)²_ = _x + y_
(x + y)(x - y) (x + y)(x - y) x - y
g)
_y + 3_ - __2__ - __4(6 + y)__
y - 3 y + 3 (y + 3)(y - 3)
m.m.c => (y + 3)(y - 3)
_(y + 3)² - 2(y - 3) - 24 - 4y_
(y + 3)(y - 3)
_y² + 6y + 9 - 2y + 6 - 24 - 4y_
(y + 3)(y -3)
__y² - 9__ = _(y + 3)(y - 3)_ = 1
(y + 3)(y - 3) (y + 3)(y - 3)
ola muitos fazem essas peguntas
a)
_2a² - 5 -a² - 3 + 9 - a²_ = _1_
a² a²
b)
_x² -2xy+ y²_ = _(x - y)²_
x²y² x²y²
c)
_a - b_ - __2__ + __1__
a(a + b) a + b b
m.m.c => ab(a + b)
_(a- b)b - 2ab + a(a + b)_
ab(a + b)
_ab - b² - 2ab + a² + ab_
ab(a + b)
_a² - b²_ = _(a + b)(a - b)_ = _(a - b)_
ab(a + b) ab(a + b) ab
d)
1 - __x²__ + __y²__ - __y__
x(x + y) y(x + y) x + y
m.m.c => xy(x + y)
_xy(x + y) - x²y + xy² - xy²_
xy(x + y)
_x²y + xy² - x²y + xy² - xy²_
xy(x + y)
__xy²__ = __y__
xy(x + y) x + y
e)
_3a + 1_ - _a + 1_
2(a - 1) a - 1
m.m.c => 2(a - 1)
_3a + 1 -2a - 2_ = _a - 1_ = _1_
2(a -1) 2(a - 1) 2
f)
__x__ + ___2y²__ + __y__
x - y (x + y)(x - y) x + y
m.m.c => (x + y)(x - y)
__x(x + y) + 2y² + y(x - y)_
(x + y)(x - y)
_x² + xy + 2y² + xy - y²_
(x + y)(x - y)
_x²+ 2xy + y^2_ = _(x + y)²_ = _x + y_
(x + y)(x - y) (x + y)(x - y) x - y
g)
_y + 3_ - __2__ - __4(6 + y)__
y - 3 y + 3 (y + 3)(y - 3)
m.m.c => (y + 3)(y - 3)
_(y + 3)² - 2(y - 3) - 24 - 4y_
(y + 3)(y - 3)
_y² + 6y + 9 - 2y + 6 - 24 - 4y_
(y + 3)(y -3)
__y² - 9__ = _(y + 3)(y - 3)_ = 1
(y + 3)(y - 3) (y + 3)(y - 3)