Question

socorro
25y ao quadrado + 10 y + 1 = 0

Answer 1

Iae, honeyy.

25y² + 10y + 1 = 0

a = 25

b = 10

c = 1

→ Determinante (∆)

∆ = b² - 4.a.c

∆ = (10)² - 4.25.1

∆ = 100 - 100

∆ = 0

→ Bháskara

X = -b ± √∆ / 2.a

X = -10 ± √0 / 2.25

X = -10 ± 0 / 50

X' = -10 + 0 / 50

X' = -10/50

X' = -1/5

X" = -10/50

X" = -1/5

É nois brother