sobre um corpo de massa 4 kg , com velocidade de 10 m/s , aplicam-se forças cuja resultante tem intensidaade 30 N , na mesma direçao e sentido da velocidade .calcule a velocidade do corpo apos percorrer 20 m
Soluções para a tarefa
Respondido por
5
Aceleração do corpo:
![F_r=30\,N\,\\ m=4\,kg \\ \\ \vec{F}_r=m\,\vec{a} \\ \\ 30=4\,a \\ \\ \boxed{a=7,\!5\,m\!/\!s^2} F_r=30\,N\,\\ m=4\,kg \\ \\ \vec{F}_r=m\,\vec{a} \\ \\ 30=4\,a \\ \\ \boxed{a=7,\!5\,m\!/\!s^2}](https://tex.z-dn.net/?f=F_r%3D30%5C%2CN%5C%2C%5C%5C+m%3D4%5C%2Ckg+%5C%5C++%5C%5C+%5Cvec%7BF%7D_r%3Dm%5C%2C%5Cvec%7Ba%7D+%5C%5C++%5C%5C+30%3D4%5C%2Ca+%5C%5C++%5C%5C+%5Cboxed%7Ba%3D7%2C%5C%215%5C%2Cm%5C%21%2F%5C%21s%5E2%7D)
Velocidade, após percorrer 20 m:
![V_0=10\,m\!/\!s \\ a=7,\!5\,m\!/\!s^2 \\ d=20\,m \\ \\ V^2=V_0^2+2\,a\,d \\ \\ V^2=10^2+2\cdot7,\!5\cdot20 \\ \\ V^2=100+300 \\ \\ V^2=400 \\ \\ \boxed{\boxed{V=20\,m\!/\!s}} V_0=10\,m\!/\!s \\ a=7,\!5\,m\!/\!s^2 \\ d=20\,m \\ \\ V^2=V_0^2+2\,a\,d \\ \\ V^2=10^2+2\cdot7,\!5\cdot20 \\ \\ V^2=100+300 \\ \\ V^2=400 \\ \\ \boxed{\boxed{V=20\,m\!/\!s}}](https://tex.z-dn.net/?f=V_0%3D10%5C%2Cm%5C%21%2F%5C%21s+%5C%5C+a%3D7%2C%5C%215%5C%2Cm%5C%21%2F%5C%21s%5E2+%5C%5C+d%3D20%5C%2Cm+%5C%5C++%5C%5C+V%5E2%3DV_0%5E2%2B2%5C%2Ca%5C%2Cd+%5C%5C++%5C%5C+V%5E2%3D10%5E2%2B2%5Ccdot7%2C%5C%215%5Ccdot20+%5C%5C++%5C%5C+V%5E2%3D100%2B300+%5C%5C++%5C%5C+V%5E2%3D400+%5C%5C++%5C%5C+%5Cboxed%7B%5Cboxed%7BV%3D20%5C%2Cm%5C%21%2F%5C%21s%7D%7D)
Velocidade, após percorrer 20 m:
Perguntas interessantes